Download PHY301 Assignment No 1 Solution 2022

 PHY301 Assignment No 1 Solution

Assignment No. 01                   PHY301: Circuit Theory

1)               First we add a resistor that is in series like V2 and V1 is in series 

R1+R2 =5Ω+2 Ω=7 Ω

Now,
As we know that V1 is in series with V2

So.

R₁+R₂ =3 Ω+7 Ω

=10 Ω

So

Now using ohm law for finding sources current
V=I_R
20_V= I 11 Ω

I_s=20V/10 Ω
I=2A

 

2)             

Determine the voltages V₁, V₂ and V₃

As we know the ohm (Ω) law

so

for V₁

 

V₁=I_s R₁

V₁=2A*3 Ω
V₁=6 Ω

For V₂

V₂=I_s R₂

=2A*5 Ω

V₂=10 Ω

 

For V₃

V₃=I_sR₃

V₃=2A*2 Ω

V₃=4 V

3)            Calculate the power dissipated by each resistors

For P₁

P₁=V₁*I_S

P₁=6V*2A

P₁=12w

For P₂

P₂=V₂I_s

10v*2A

P₂=20W

For P₃

P₃=V₃*I_s

4v*2A

P₃=8W

4)            Determine the powe delivered by the source  and compare it to the sum of the power

levels of part (4)

Power dissipation of source will be

P_s=I_s*V_s

P_s=2A-20V

P_s=40W

Sum and compare

P_s=P₁+P₂+P₃

P_s =12W+20W+8W

40W=40W

Q2 ANSWER

1)             

Whenever a crow is roosted on a solitary wire of 100KV its two feet are at similar electrical potential of 100KV so the electrons in the wire have no inspiration to go through the crew’s body. No mowing electrons implies no electric flow.

 

2)             

Silicon	Semiconductor
Silver	Conductor
iron	Conductor
carbon	Insulator
glass	Insulator
copper	Conductor
Rubber	Insulator