Cs601 Assignment No 2 Solution Fall 2017

CS601 (Data Communication)

Assignment No. 2

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Question No.1:                                                                                                                  

Consider a noisy channel, which has a bandwidth of 400KHz and theoretical channel capacity of 4.01Mbps (according to Shannon Capacity formula).

Calculate the Signal Power received at the receiver end if the Noise Power is .001 Watt.

Calculation	Answers with proper Units
a) Calculation of Signal Power using Shannon Capacity Formula: Now,  Putting the values in Shannon Capacity Formula:	Signal Power = 1.041watt

b.      Also calculate the signal to noise ratio of the channel in dB (SNR_dB).

Question No. 2:                                                                                                                                              

A signal of power 6 mW is transmitted through a cable. If the signal encounters a loss of 6db due to impairments of the transmission medium. Calculate the power received at the receiver end.

Calculation	Relative signal strength before and after power loss with unit
Data Provided: Loss in signal therefor dB = -6 Signal Power P1 = 6mW We can calculate the power P2 as:	Before Power Loss = 6mW After Power Loss = 6mW – 1.5mW = 4.5mW